Conditions for Simple Harmonic Motion (SHM)
Simple Harmonic Motion (SHM) is a special type of oscillatory motion where an object moves back and forth around an equilibrium position.
Restoring Force Proportional to Displacement
- For SHM to occur, the system must have a restoring force that:
- Acts in the opposite direction to the displacement.
- Is directly proportional to the displacement from the equilibrium position.
- This relationship can be expressed mathematically as: $$
F = -kx
$$ where:- $F$ is the restoring force.
- $k$ is a constant (often called the spring constant in a spring-mass system).
- $x$is the displacement from the equilibrium position.
The negative sign indicates that the force acts in the opposite direction to the displacement.
- In a mass-spring system, when the mass is displaced to the right, the spring exerts a force to the left, trying to bring the mass back to equilibrium.
- This force is proportional to how far the mass is stretched or compressed.
Acceleration in SHM
- The restoring force causes the object to accelerate back towards the equilibrium position.
- Using Newton’s second law, $F = ma$, we can express the acceleration as: $$
a = -\frac{k}{m}x
$$ - This shows that the acceleration is also proportional to the displacement and acts in the opposite direction.
Defining Equation for SHM: $a = -\omega^2 x$
The defining equation for SHM is:
$$
a = -\omega^2 x
$$
where:
- $a$ is the acceleration.
- $x$ is the displacement.
- $\omega$ (omega) is the angular frequency, a constant that characterizes the system.
The negative sign indicates that the acceleration is always directed opposite to the displacement, ensuring the object is pulled back towards equilibrium.
Why $a = -\omega^2 x$?
- The term $\omega^2$ is derived from the system’s properties.
- In a mass-spring system, for example, $\omega^2 = \frac{k}{m}$, where $k$ is the spring constant and $m$ is the mass.
This relationship highlights how the system’s physical characteristics determine its oscillatory behavior.
- The negative sign in $a = -\omega^2 x$ is crucial.
- It ensures that the acceleration always opposes the displacement, a fundamental requirement for SHM.
Key Parameters of SHM
To fully describe SHM, we need to understand several key parameters:
Amplitude, Equilibrium Position, and Displacement
- Amplitude ($A$):
- The maximum displacement from the equilibrium position.
- It represents the furthest point the object reaches during its oscillation.
- Equilibrium Position:
- The point where the net force on the object is zero.
- In SHM, the object oscillates symmetrically around this position.
- Displacement ($x$):
- The distance of the object from the equilibrium position at any given time.
- Displacement can be positive or negative, depending on the direction.
- If a pendulum swings 5 cm to the right and 5 cm to the left of its equilibrium position, its amplitude is 5 cm.
- The displacement varies between +5 cm and -5 cm during the oscillation.
Time Period ($T$), Frequency ($f$), and Angular Frequency ($\omega$)
These parameters describe the timing of the oscillation:
- Time Period ($T$): The time taken to complete one full oscillation. It is measured in seconds (s).
- Frequency ($f$): The number of oscillations per second. It is measured in hertz (Hz) and is the inverse of the period: $$
f = \frac{1}{T}
$$ - Angular Frequency ($\omega$): A measure of how quickly the object oscillates, expressed in radians per second (rad/s). It is related to the period and frequency by: $$
\omega = 2\pi f = \frac{2\pi}{T}
$$
A mass-spring system with a period of 2 seconds has a frequency of 0.5 Hz and an angular frequency of: $$\omega = 2\pi \times 0.5 = \pi \text{ rad s}^{-1}$$
- What are the conditions for a system to exhibit SHM?
- How is the angular frequency ($\omega$) related to the period ($T$) and frequency ($f$)?
- Why is the acceleration in SHM always directed opposite to the displacement?


