Understanding Momentum and Impulse
- You're playing a game of billiards.
- You strike the cue ball, and it collides with another ball, sending both rolling across the table.
- What determines how these balls move after the collision?
The answer lies in two fundamental concepts: momentum and impulse.
What is Momentum?
Momentum
Momentum is a measure of how difficult it is to stop a moving object. It depends on two factors: the object's mass and its velocity.
Definition of Momentum
Momentum is defined as the product of an object's mass and its velocity:
$$
\vec{p} = m \vec{v}
$$
where $\vec{p}$ is the momentum (in $\text{kg m s}^{-1}$), $m$ is the mass (in $\text{kg}$), $\vec{v}$ is the velocity (in $\text{m s}^{-1}$).
Newton originally expressed his Second Law in terms of momentum rather than acceleration.
He stated that:
"the rate of change of momentum of an object is proportional to the force applied, and takes place in the direction of the force."
This can be written as:
$$
\vec{F} = \frac{\Delta\vec{p}}{\Delta t}
$$
- This form is particularly useful when dealing with systems where the mass is not constant, such as a rocket.
- As a rocket burns fuel, it ejects mass backward and becomes lighter over time.
- Even though the total system’s mass is changing, the force generated by the rocket engines can still be understood as the rate of change of momentum.
- For example, if a rocket expels gas backward at high velocity, the momentum of the expelled gas increases in one direction, and by conservation of momentum, the rocket gains momentum in the opposite direction.
- This causes the rocket to accelerate.
- Continuing from example about the rocket, since its mass is decreasing, the simple form $$\vec{F} = m \vec{a}$$ is not sufficient.
- Instead, we rely on: $$\vec{F} = \frac{\Delta \vec{p}}{\Delta t}$$
- It could be written more rigorously as: $$\vec{F} = \frac{d}{dt}(m \vec{v})$$ which accounts for both the changing velocity and changing mass of the rocket.
- When the mass is constant, this equation simplifies to the more familiar form: $$\vec{F} = m \frac{d\vec{v}}{dt} = m \vec{a}$$
Why is Momentum Important?
- Momentum helps us understand how objects behave during interactions like collisions or explosions.
- It is a conserved quantity (we prove it further), meaning the total momentum of a system remains constant if no external forces act on it.
- Momentum is a vector quantity, so direction must be considered when applying this principle.
- When convenient, one may define the axes in the framework of the problem and work with projections instead.
Impulse: Changing Momentum
Impulse
Impulse describes how a force applied over a period of time changes an object's momentum.
Impulse-Momentum Theorem
Impulse-momentum theorem
The impulse-momentum theorem states that the impulse on an object is equal to the change in its momentum
- The impulse–momentum theorem relates the force acting on an object to the change in its momentum: $\vec{F} \Delta t = \Delta \vec{p}$$
- Impulse is defined as the product of force and the time interval over which the force acts: $$\vec{J} = \vec{F} \Delta t$$
Impulse has the same units as momentum ($\text{kg m s}^{-1}$), and is also a vector quantity.
- This relationship shows that a force acting for a short time can produce the same change in momentum as a smaller force acting over a longer time.
- For example, when catching a ball, moving your hands backward increases the time over which the ball’s momentum is brought to zero, reducing the force you feel.
- This is a practical application of the impulse–momentum theorem.
- If the force is not constant, we shall sum product of force and small time interval (small enough to regard the force acting on a body during it to be constant) over the time interval during which the force is applied to the body. $$\vec{J} = \Delta \vec{p} = \sum \vec{F} \Delta t$$
- Mathematically, in the limit $\Delta t \to 0$ the impulse is the integral of force over time: $$\vec{J} = \int \vec{F} \, dt$$
Geometrically the above represents the area under force-time graph.
Impulse is also a vector quantity, sharing the same direction as the force applied.
Calculating Impulse
Impulse can be calculated in two ways:
- Using the formula $J = F \Delta t$ for constant forces.
- By finding the area under a force-time graph for variable forces.
A 0.5 kg ball moving at $4 \text{ m s}^{-1}$ hits a wall and rebounds at $-2 \text{ m s}^{-1}$. Calculate the average force exerted by the wall on the ball.
Solution
- The change in momentum is: $$\Delta \mathbf{p} = m \Delta \mathbf{v} $$ $$=0.5 \, \text{kg} \times ( -2 \, \text{m s}^{-1} - 4 \, \text{ m s}^{-1}) = -3 \, \text{kg m s}^{-1}$$
- If the ball is in contact with the wall for 0.15 s, the average force exerted is: $$\mathbf{F} = \frac{\Delta \mathbf{p}}{\Delta t} $$ $$= \frac{-3 \, \text{kg m s}^{-1}}{0.15 \, \text{s}} = -20 \, \text{N}$$
- The negative sign indicates the force is in the opposite direction of the initial motion.
Conservation of Momentum
The law of conservation of momentum
The law of conservation of momentum states that the total momentum of an isolated system remains constant if no external forces act on it.
- We shall thus prove the principle of conservation of momentum.
- In an isolated system, where no external forces act, the total momentum of the system remains constant.
- To see why this is true, we start with Newton’s Second Law in its original form: $$\vec{F}_{\text{net}} = \frac{\Delta \vec{p}}{\Delta t}$$
- If there are no external forces acting on the system, then: $$\vec{F}_{\text{net}} = 0$$
- This implies: $$\frac{\Delta\vec{p}}{\Delta t} = 0$$
- This means that the rate of change of momentum is zero.
- Therefore, the total momentum of the system does not change with time: $$\vec{p}_{\text{total}} = \text{constant}$$
- This means that in any interaction (such as a collision or explosion) within a isolated system (collection of objects that do not interact with anything outside of that collection), the total momentum before the interaction equals the total momentum after the interaction: $$\sum \vec{p}_{\text{before}} = \sum \vec{p}_{\text{after}}$$
A common mistake is to assume that a larger force always produces a greater impulse.
- Remember, impulse depends on both the force and the time duration.
- A smaller force applied over a longer time can produce the same impulse as a larger force applied briefly.
- How is impulse related to the change in momentum?
- Why is momentum conserved in an isolated system?
- How do airbags and crumple zones use the impulse-momentum theorem to enhance safety?


