Power: The Rate of Doing Work
Power
Power is the rate at which energy is transferred or converted.
Mathematically, power ($P$) is defined as the rate of doing work ($W$) over a time interval ($\Delta t$):
$$
P = \frac{W}{\Delta t}
$$
The unit of power is the watt (W), where 1 watt equals 1 joule per second (1 W = 1 J/s).
If a motor does 500 J of work in 10 seconds, its power is:
$$
P = \frac{500 \, \text{J}}{10 \, \text{s}} = 50 \, \text{W}
$$
Power Delivered by a Force
- For a constant force ($F$) moving an object at velocity ($v$), power is given by: $$P = Fv$$
- It applies when the force and velocity are in the same direction, measuring power in watts ($\text{W}$).
- If the force and velocity are not aligned, the equation generalizes to $$P = Fv\cos\theta$$ where $\theta$ is the angle between the force and velocity.
This formula highlights the relationship between force, velocity, and power.
A car engine exerts a force of 1,000 N to maintain a speed of $20 \ \text{m s}^{-1}$. The power output is: $$
P = Fv = 1,000 \, \text{N} \times 20 \, \text{m s}^{-1}$$
$$ = 20,000 \, \text{W} \, (20 \, \text{kW})
$$
The formula $P = Fv$ is especially useful for systems with constant velocity, such as vehicles cruising at steady speeds.
Efficiency: Measuring Energy Transfer Effectiveness
Efficiency
Efficiency quantifies how effectively a system converts input energy into useful output energy.
It is expressed as a ratio or percentage:
$$
\eta = \frac{E_{\text{output}}}{E_{\text{input}}} \times 100%
$$
Efficiency is always less than 100% due to energy losses, often as heat or sound.
- An electric motor receives 500 J of electrical energy and outputs 350 J of mechanical work.
- Its efficiency is:
$$
\eta = \frac{350 \, \text{J}}{500 \, \text{J}} \times 100\% = 70\%
$$
Efficiency is a dimensionless quantity, often expressed as a percentage.
Efficiency can also be calculated as a ratio of powers instead of a ratio of energies.
Energy Density
Energy density
Energy density is defined as the amount of energy stored per unit volume or mass of a substance.
- It can be expressed in two ways:
- Volumetric Energy Density: Energy per unit volume ($\mathrm{J \ m}^{-3}$)
- Gravimetric Energy Density: Energy per unit mass ($\mathrm{J \ kg}^{-1}$)
- High energy-density fuels can store large amounts of energy in a small amount of space, making them efficient for transportation and storage.
- The energy density can be expressed using these equations:
- For volumetric energy density: $$e_v=\frac{E}{V}$$
- For gravimetric energy density: $$e_m=\frac{E}{m}$$ where:
- $e_v$ is volumetric energy density ($\mathrm{J \ m}^{-3}$)
- $e_m$ is gravimetric energy density ($\mathrm{J \ kg}^{-1}$)
- $E$ is energy ($\mathrm{J}$)
- $V$ is volume ($\mathrm{m}^3$)
- $m$ is mass ($\mathrm{kg}$)
Volumetric and Gravimetric Energy Densities
A fuel contains $5.0 \times 10^7 \, \mathrm{J}$ of energy. Its mass is $2.5 \, \mathrm{kg}$, and its volume is $0.002 \, \mathrm{m}^3$.
Calculate the volumetric energy density and gravimetric energy density.
Solution
Volumetric Energy Density ($e_v$):
- The volumetric energy density is calculated as: $$e_v = \frac{E}{V}$$
- Substitute the values: $$e_v = \frac{5.0 \times 10^7 \, \mathrm{J}}{0.002 \, \mathrm{m}^3}$$ $$e_v=2.5 \times 10^{10} \, \mathrm{J \ m}^{-3}$$
Gravimetric Energy Density ($e_m$):
- The gravimetric energy density is calculated as: $$e_m = \frac{E}{m}$$
- Substitute the values: $$e_m = \frac{5.0 \times 10^7 \, \mathrm{J}}{2.5 \, \mathrm{kg}}$$ $$e_m=2.0 \times 10^7 \, \mathrm{J \ kg}^{-1}$$
Results:
- Volumetric Energy Density: $2.5 \times 10^{10} \, \mathrm{J \ m}^{-3}$
- Gravimetric Energy Density: $2.0 \times 10^7 \, \mathrm{J \ kg}^{-1}$
Applications of Power in Real-World Systems
Engines
- Engines convert fuel energy into mechanical work.
- Their power output determines performance, such as acceleration and towing capacity.
A car engine rated at 150 kW can accelerate faster than one rated at 100 kW, assuming similar efficiency.
Electric Appliances
- Power ratings on appliances indicate energy consumption.
- A 100 W light bulb uses 100 J of energy per second, while a 1,500 W heater consumes 1,500 J per second.
When comparing appliances, consider both power rating and efficiency to assess energy cost and performance.
- What is the formula for power in terms of work and time?
- How does $P = Fv$ relate power to force and velocity?
- Why is efficiency always less than 100% in real-world systems?


